92+3(x+4)=7(3x+18)

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Solution for 92+3(x+4)=7(3x+18) equation: 



92+3(x+4)=7(3x+18)

We move all terms to the left:

92+3(x+4)-(7(3x+18))=0

We multiply parentheses

3x-(7(3x+18))+12+92=0



We calculate terms in parentheses: -(7(3x+18)), so:

7(3x+18)

We multiply parentheses

21x+126

Back to the equation:

-(21x+126)



We add all the numbers together, and all the variables

3x-(21x+126)+104=0

We get rid of parentheses

3x-21x-126+104=0

We add all the numbers together, and all the variables

-18x-22=0

We move all terms containing x to the left, all other terms to the right

-18x=22

x=22/-18

x=-1+2/9

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