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X2-45X+324=0
We add all the numbers together, and all the variables
X^2-45X+324=0
a = 1; b = -45; c = +324;
Δ = b2-4ac
Δ = -452-4·1·324
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-27}{2*1}=\frac{18}{2} =9 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+27}{2*1}=\frac{72}{2} =36 $
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