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10(x-1)=2(2x+5)
We move all terms to the left:
10(x-1)-(2(2x+5))=0
We multiply parentheses
10x-(2(2x+5))-10=0
We calculate terms in parentheses: -(2(2x+5)), so:We get rid of parentheses
2(2x+5)
We multiply parentheses
4x+10
Back to the equation:
-(4x+10)
10x-4x-10-10=0
We add all the numbers together, and all the variables
6x-20=0
We move all terms containing x to the left, all other terms to the right
6x=20
x=20/6
x=3+1/3
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