6(x+2)-2=x-4+x

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Solution for 6(x+2)-2=x-4+x equation: 



6(x+2)-2=x-4+x

We move all terms to the left:

6(x+2)-2-(x-4+x)=0

We add all the numbers together, and all the variables

6(x+2)-(2x-4)-2=0

We multiply parentheses

6x-(2x-4)+12-2=0

We get rid of parentheses

6x-2x+4+12-2=0

We add all the numbers together, and all the variables

4x+14=0

We move all terms containing x to the left, all other terms to the right

4x=-14

x=-14/4

x=-3+1/2

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