3-(4w+5)=1/2(8w=28)

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Solution for 3-(4w+5)=1/2(8w=28) equation: 



3-(4w+5)=1/2(8w=28)

We move all terms to the left:

3-(4w+5)-(1/2(8w)=0



Domain of the equation: 28w+3!=0

We move all terms containing w to the left, all other terms to the right

28w!=-3

w!=-3/28

w!=-3/28

w∈R



We get rid of parentheses

-4w-(1/28w+3-5=0

We multiply all the terms by the denominator


-4w*28w+3-5-(1=0

We add all the numbers together, and all the variables

-4w*28w=0

Wy multiply elements

-112w^2=0

a = -112; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-112)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$w=\frac{-b}{2a}=\frac{0}{-224}=0$

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