10(x-1)+(x+4)+4x=288

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Solution for 10(x-1)+(x+4)+4x=288 equation: 



10(x-1)+(x+4)+4x=288

We move all terms to the left:

10(x-1)+(x+4)+4x-(288)=0

We add all the numbers together, and all the variables

4x+10(x-1)+(x+4)-288=0

We multiply parentheses

4x+10x+(x+4)-10-288=0

We get rid of parentheses

4x+10x+x+4-10-288=0

We add all the numbers together, and all the variables

15x-294=0

We move all terms containing x to the left, all other terms to the right

15x=294

x=294/15

x=19+3/5

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