-(x-1)+8(1+3x)=x+3+6-7x

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Solution for -(x-1)+8(1+3x)=x+3+6-7x equation: 



-(x-1)+8(1+3x)=x+3+6-7x

We move all terms to the left:

-(x-1)+8(1+3x)-(x+3+6-7x)=0

We add all the numbers together, and all the variables

-(x-1)+8(3x+1)-(-6x+9)=0

We multiply parentheses

-(x-1)+24x-(-6x+9)+8=0

We get rid of parentheses

-x+24x+6x+1-9+8=0

We add all the numbers together, and all the variables

29x=0

x=0/29

x=0

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