-5-2v=1-2(1+2v)

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Solution for -5-2v=1-2(1+2v) equation: 



-5-2v=1-2(1+2v)

We move all terms to the left:

-5-2v-(1-2(1+2v))=0

We add all the numbers together, and all the variables

-2v-(1-2(2v+1))-5=0



We calculate terms in parentheses: -(1-2(2v+1)), so:

1-2(2v+1)

determiningTheFunctionDomain
-2(2v+1)+1

We multiply parentheses

-4v-2+1

We add all the numbers together, and all the variables

-4v-1

Back to the equation:

-(-4v-1)



We get rid of parentheses

-2v+4v+1-5=0

We add all the numbers together, and all the variables

2v-4=0

We move all terms containing v to the left, all other terms to the right

2v=4

v=4/2

v=2

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