288=10(x-1)+(x+4)+4x

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Solution for 288=10(x-1)+(x+4)+4x equation: 



288=10(x-1)+(x+4)+4x

We move all terms to the left:

288-(10(x-1)+(x+4)+4x)=0



We calculate terms in parentheses: -(10(x-1)+(x+4)+4x), so:

10(x-1)+(x+4)+4x

We add all the numbers together, and all the variables

4x+10(x-1)+(x+4)

We multiply parentheses

4x+10x+(x+4)-10

We get rid of parentheses

4x+10x+x+4-10

We add all the numbers together, and all the variables

15x-6

Back to the equation:

-(15x-6)



We get rid of parentheses

-15x+6+288=0

We add all the numbers together, and all the variables

-15x+294=0

We move all terms containing x to the left, all other terms to the right

-15x=-294

x=-294/-15

x=19+3/5

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