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1/9(9y+18)-8=-1/2(6y-12)
We move all terms to the left:
1/9(9y+18)-8-(-1/2(6y-12))=0
Domain of the equation: 9(9y+18)!=0
y∈R
Domain of the equation: 2(6y-12))!=0We calculate fractions
y∈R
(2y6/(9(9y+18)*2(6y-12)))+(-(-9y9)/(9(9y+18)*2(6y-12)))-8=0
We calculate terms in parentheses: +(2y6/(9(9y+18)*2(6y-12))), so:
2y6/(9(9y+18)*2(6y-12))
We multiply all the terms by the denominator
2y6
We add all the numbers together, and all the variables
2y^6
We do not support eypression: y^6
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