((x-3)-3)+(2/3x)=12

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Solution for ((x-3)-3)+(2/3x)=12 equation: 



((x-3)-3)+(2/3x)=12

We move all terms to the left:

((x-3)-3)+(2/3x)-(12)=0



Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

((x-3)-3)+(+2/3x)-12=0

We get rid of parentheses

((x-3)-3)+2/3x-12=0

We multiply all the terms by the denominator


(((x-3)-3))*3x-12*3x+2=0

Wy multiply elements

(((x-3)-3))*3x-36x+2=0

We add all the numbers together, and all the variables

-36x+(((x-3)-3))*3x+2=0

We move all terms containing x to the left, all other terms to the right

-36x+(((x-3)-3))*3x=-2

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