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12x^2-10=25
We move all terms to the left:
12x^2-10-(25)=0
We add all the numbers together, and all the variables
12x^2-35=0
a = 12; b = 0; c = -35;
Δ = b2-4ac
Δ = 02-4·12·(-35)
Δ = 1680
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1680}=\sqrt{16*105}=\sqrt{16}*\sqrt{105}=4\sqrt{105}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{105}}{2*12}=\frac{0-4\sqrt{105}}{24} =-\frac{4\sqrt{105}}{24} =-\frac{\sqrt{105}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{105}}{2*12}=\frac{0+4\sqrt{105}}{24} =\frac{4\sqrt{105}}{24} =\frac{\sqrt{105}}{6} $
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