3(y-5)+2(y-11)=24

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Solution for 3(y-5)+2(y-11)=24 equation: 



3(y-5)+2(y-11)=24

We move all terms to the left:

3(y-5)+2(y-11)-(24)=0

We multiply parentheses

3y+2y-15-22-24=0

We add all the numbers together, and all the variables

5y-61=0

We move all terms containing y to the left, all other terms to the right

5y=61

y=61/5

y=12+1/5

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