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1/5x+2/5x-2=7
We move all terms to the left:
1/5x+2/5x-2-(7)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
1/5x+2/5x-9=0
We multiply all the terms by the denominator
-9*5x+1+2=0
We add all the numbers together, and all the variables
-9*5x+3=0
Wy multiply elements
-45x+3=0
We move all terms containing x to the left, all other terms to the right
-45x=-3
x=-3/-45
x=1/15
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