x+(x-5)+(x-5/2)=100

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Solution for x+(x-5)+(x-5/2)=100 equation: 



x+(x-5)+(x-5/2)=100

We move all terms to the left:

x+(x-5)+(x-5/2)-(100)=0

We add all the numbers together, and all the variables

x+(x-5)+(+x-5/2)-100=0

We get rid of parentheses

x+x+x-5-100-5/2=0

We multiply all the terms by the denominator


x*2+x*2+x*2-5-5*2-100*2=0

We add all the numbers together, and all the variables

x*2+x*2+x*2-215=0

Wy multiply elements

2x+2x+2x-215=0

We add all the numbers together, and all the variables

6x-215=0

We move all terms containing x to the left, all other terms to the right

6x=215

x=215/6

x=35+5/6

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