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14(v+2)-2v=4(3v+2)-10
We move all terms to the left:
14(v+2)-2v-(4(3v+2)-10)=0
We add all the numbers together, and all the variables
-2v+14(v+2)-(4(3v+2)-10)=0
We multiply parentheses
-2v+14v-(4(3v+2)-10)+28=0
We calculate terms in parentheses: -(4(3v+2)-10), so:We add all the numbers together, and all the variables
4(3v+2)-10
We multiply parentheses
12v+8-10
We add all the numbers together, and all the variables
12v-2
Back to the equation:
-(12v-2)
12v-(12v-2)+28=0
We get rid of parentheses
12v-12v+2+28=0
We add all the numbers together, and all the variables
30!=0
There is no solution for this equation
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