1/3x+1/4x=14

Solution for 1/3x+1/4x=14 equation:

1/3x+1/4x=14

We move all terms to the left:

1/3x+1/4x-(14)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R


We calculate fractions


4x/12x^2+3x/12x^2-14=0

We multiply all the terms by the denominator


4x+3x-14*12x^2=0

We add all the numbers together, and all the variables

7x-14*12x^2=0

Wy multiply elements

-168x^2+7x=0

a = -168; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·(-168)·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*-168}=\frac{-14}{-336}
=1/24
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*-168}=\frac{0}{-336}
=0
$