1/7(3x-5)=2/7x+2

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Solution for 1/7(3x-5)=2/7x+2 equation: 



1/7(3x-5)=2/7x+2

We move all terms to the left:

1/7(3x-5)-(2/7x+2)=0



Domain of the equation: 7(3x-5)!=0

x∈R





Domain of the equation: 7x+2)!=0

x∈R



We get rid of parentheses

1/7(3x-5)-2/7x-2=0

We calculate fractions


7x/(147x^2-245x)+(-14x3/(147x^2-245x)-2=0

We calculate fractions

We do not support expression: x^3

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