0=(2a+1)-(4a+2)

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Solution for 0=(2a+1)-(4a+2) equation: 



0=(2a+1)-(4a+2)

We move all terms to the left:

0-((2a+1)-(4a+2))=0

We add all the numbers together, and all the variables

-((2a+1)-(4a+2))=0



We calculate terms in parentheses: -((2a+1)-(4a+2)), so:

(2a+1)-(4a+2)

We get rid of parentheses

2a-4a+1-2

We add all the numbers together, and all the variables

-2a-1

Back to the equation:

-(-2a-1)



We get rid of parentheses

2a+1=0

We move all terms containing a to the left, all other terms to the right

2a=-1

a=-1/2

a=-1/2

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