24(b-1)+12=3(8b-4)

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Solution for 24(b-1)+12=3(8b-4) equation: 



24(b-1)+12=3(8b-4)

We move all terms to the left:

24(b-1)+12-(3(8b-4))=0

We multiply parentheses

24b-(3(8b-4))-24+12=0



We calculate terms in parentheses: -(3(8b-4)), so:

3(8b-4)

We multiply parentheses

24b-12

Back to the equation:

-(24b-12)



We add all the numbers together, and all the variables

24b-(24b-12)-12=0

We get rid of parentheses

24b-24b+12-12=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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