1/3(z+6)=1/2(z-3)

Solution for 1/3(z+6)=1/2(z-3) equation:

1/3(z+6)=1/2(z-3)

We move all terms to the left:

1/3(z+6)-(1/2(z-3))=0


Domain of the equation: 3(z+6)!=0

z∈R



Domain of the equation: 2(z-3))!=0

z∈R


We calculate fractions


(2zz/(3(z+6)*2(z-3)))+(-3zz/(3(z+6)*2(z-3)))=0


We calculate terms in parentheses: +(2zz/(3(z+6)*2(z-3))), so:

2zz/(3(z+6)*2(z-3))

We multiply all the terms by the denominator


2zz

Back to the equation:

+(2zz)



We calculate terms in parentheses: +(-3zz/(3(z+6)*2(z-3))), so:

-3zz/(3(z+6)*2(z-3))

We multiply all the terms by the denominator


-3zz

Back to the equation:

+(-3zz)


We get rid of parentheses

2zz-3zz=0