1/3(x-5)=1/2(x+3)

Solution for 1/3(x-5)=1/2(x+3) equation:

1/3(x-5)=1/2(x+3)

We move all terms to the left:

1/3(x-5)-(1/2(x+3))=0


Domain of the equation: 3(x-5)!=0

x∈R



Domain of the equation: 2(x+3))!=0

x∈R


We calculate fractions


(2xx/(3(x-5)*2(x+3)))+(-3xx/(3(x-5)*2(x+3)))=0


We calculate terms in parentheses: +(2xx/(3(x-5)*2(x+3))), so:

2xx/(3(x-5)*2(x+3))

We multiply all the terms by the denominator


2xx

Back to the equation:

+(2xx)



We calculate terms in parentheses: +(-3xx/(3(x-5)*2(x+3))), so:

-3xx/(3(x-5)*2(x+3))

We multiply all the terms by the denominator


-3xx

Back to the equation:

+(-3xx)


We get rid of parentheses

2xx-3xx=0