1=1/2(2a+2)

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Solution for 1=1/2(2a+2) equation: 



1=1/2(2a+2)

We move all terms to the left:

1-(1/2(2a+2))=0



Domain of the equation: 2(2a+2))!=0

a∈R



We multiply all the terms by the denominator


-(1+1*2(2a+2))=0



We calculate terms in parentheses: -(1+1*2(2a+2)), so:

1+1*2(2a+2)

determiningTheFunctionDomain
1*2(2a+2)+1

Wy multiply elements

2a(2+1

Back to the equation:

-(2a(2+1)



We add all the numbers together, and all the variables

-(2a3=0

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