-(4t-2)-(2t-3)=23-(2t+2)

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Solution for -(4t-2)-(2t-3)=23-(2t+2) equation: 



-(4t-2)-(2t-3)=23-(2t+2)

We move all terms to the left:

-(4t-2)-(2t-3)-(23-(2t+2))=0

We get rid of parentheses

-4t-2t-(23-(2t+2))+2+3=0



We calculate terms in parentheses: -(23-(2t+2)), so:

23-(2t+2)

determiningTheFunctionDomain
-(2t+2)+23

We get rid of parentheses

-2t-2+23

We add all the numbers together, and all the variables

-2t+21

Back to the equation:

-(-2t+21)



We add all the numbers together, and all the variables

-6t-(-2t+21)+5=0

We get rid of parentheses

-6t+2t-21+5=0

We add all the numbers together, and all the variables

-4t-16=0

We move all terms containing t to the left, all other terms to the right

-4t=16

t=16/-4

t=-4

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