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(2x+10)(2x+34)=640
We move all terms to the left:
(2x+10)(2x+34)-(640)=0
We multiply parentheses ..
(+4x^2+68x+20x+340)-640=0
We get rid of parentheses
4x^2+68x+20x+340-640=0
We add all the numbers together, and all the variables
4x^2+88x-300=0
a = 4; b = 88; c = -300;
Δ = b2-4ac
Δ = 882-4·4·(-300)
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{12544}=112$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(88)-112}{2*4}=\frac{-200}{8} =-25 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(88)+112}{2*4}=\frac{24}{8} =3 $
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