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1/3(x-4)-x=3(5-x)
We move all terms to the left:
1/3(x-4)-x-(3(5-x))=0
Domain of the equation: 3(x-4)!=0We add all the numbers together, and all the variables
x∈R
1/3(x-4)-x-(3(-1x+5))=0
We add all the numbers together, and all the variables
-1x+1/3(x-4)-(3(-1x+5))=0
We multiply all the terms by the denominator
-1x*3(x-4)-((3(-1x+5)))*3(x-4)+1=0
We calculate terms in parentheses: -((3(-1x+5)))*3(x-4), so:Wy multiply elements
(3(-1x+5)))*3(x-4
-3x^2(x-((3(-1x+5)))*3(x-4)+1=0
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