5=2(k+2)-1

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Solution for 5=2(k+2)-1 equation: 



5=2(k+2)-1

We move all terms to the left:

5-(2(k+2)-1)=0



We calculate terms in parentheses: -(2(k+2)-1), so:

2(k+2)-1

We multiply parentheses

2k+4-1

We add all the numbers together, and all the variables

2k+3

Back to the equation:

-(2k+3)



We get rid of parentheses

-2k-3+5=0

We add all the numbers together, and all the variables

-2k+2=0

We move all terms containing k to the left, all other terms to the right

-2k=-2

k=-2/-2

k=1

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