3(2x-3)=19-2(5-3x)+9x

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Solution for 3(2x-3)=19-2(5-3x)+9x equation: 



3(2x-3)=19-2(5-3x)+9x

We move all terms to the left:

3(2x-3)-(19-2(5-3x)+9x)=0

We add all the numbers together, and all the variables

3(2x-3)-(19-2(-3x+5)+9x)=0

We multiply parentheses

6x-(19-2(-3x+5)+9x)-9=0



We calculate terms in parentheses: -(19-2(-3x+5)+9x), so:

19-2(-3x+5)+9x

determiningTheFunctionDomain
-2(-3x+5)+9x+19

We add all the numbers together, and all the variables

9x-2(-3x+5)+19

We multiply parentheses

9x+6x-10+19

We add all the numbers together, and all the variables

15x+9

Back to the equation:

-(15x+9)



We get rid of parentheses

6x-15x-9-9=0

We add all the numbers together, and all the variables

-9x-18=0

We move all terms containing x to the left, all other terms to the right

-9x=18

x=18/-9

x=-2

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