2(r-3)=3+r

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Solution for 2(r-3)=3+r equation: 



2(r-3)=3+r

We move all terms to the left:

2(r-3)-(3+r)=0

We add all the numbers together, and all the variables

2(r-3)-(r+3)=0

We multiply parentheses

2r-(r+3)-6=0

We get rid of parentheses

2r-r-3-6=0

We add all the numbers together, and all the variables

r-9=0

We move all terms containing r to the left, all other terms to the right

r=9

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