1/3(9x+3)=x+7

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Solution for 1/3(9x+3)=x+7 equation: 



1/3(9x+3)=x+7

We move all terms to the left:

1/3(9x+3)-(x+7)=0



Domain of the equation: 3(9x+3)!=0

x∈R



We get rid of parentheses

1/3(9x+3)-x-7=0

We multiply all the terms by the denominator


-x*3(9x+3)-7*3(9x+3)+1=0

Wy multiply elements

-3x^2(9-21x(9+1=0

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