3(x-5)+1-x=2(2x+1)

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Solution for 3(x-5)+1-x=2(2x+1) equation: 



3(x-5)+1-x=2(2x+1)

We move all terms to the left:

3(x-5)+1-x-(2(2x+1))=0

We add all the numbers together, and all the variables

-1x+3(x-5)-(2(2x+1))+1=0

We multiply parentheses

-1x+3x-(2(2x+1))-15+1=0



We calculate terms in parentheses: -(2(2x+1)), so:

2(2x+1)

We multiply parentheses

4x+2

Back to the equation:

-(4x+2)



We add all the numbers together, and all the variables

2x-(4x+2)-14=0

We get rid of parentheses

2x-4x-2-14=0

We add all the numbers together, and all the variables

-2x-16=0

We move all terms containing x to the left, all other terms to the right

-2x=16

x=16/-2

x=-8

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