4(a-5)+3a=2a+10

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Solution for 4(a-5)+3a=2a+10 equation: 



4(a-5)+3a=2a+10

We move all terms to the left:

4(a-5)+3a-(2a+10)=0

We add all the numbers together, and all the variables

3a+4(a-5)-(2a+10)=0

We multiply parentheses

3a+4a-(2a+10)-20=0

We get rid of parentheses

3a+4a-2a-10-20=0

We add all the numbers together, and all the variables

5a-30=0

We move all terms containing a to the left, all other terms to the right

5a=30

a=30/5

a=6

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