7c-(3c+4)=-2(2c-1)+10

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Solution for 7c-(3c+4)=-2(2c-1)+10 equation: 



7c-(3c+4)=-2(2c-1)+10

We move all terms to the left:

7c-(3c+4)-(-2(2c-1)+10)=0

We get rid of parentheses

7c-3c-(-2(2c-1)+10)-4=0



We calculate terms in parentheses: -(-2(2c-1)+10), so:

-2(2c-1)+10

We multiply parentheses

-4c+2+10

We add all the numbers together, and all the variables

-4c+12

Back to the equation:

-(-4c+12)



We add all the numbers together, and all the variables

4c-(-4c+12)-4=0

We get rid of parentheses

4c+4c-12-4=0

We add all the numbers together, and all the variables

8c-16=0

We move all terms containing c to the left, all other terms to the right

8c=16

c=16/8

c=2

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