-r+5(-3-2r)=2+4(2-2r)

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Solution for -r+5(-3-2r)=2+4(2-2r) equation: 



-r+5(-3-2r)=2+4(2-2r)

We move all terms to the left:

-r+5(-3-2r)-(2+4(2-2r))=0

We add all the numbers together, and all the variables

-r+5(-2r-3)-(2+4(-2r+2))=0

We add all the numbers together, and all the variables

-1r+5(-2r-3)-(2+4(-2r+2))=0

We multiply parentheses

-1r-10r-(2+4(-2r+2))-15=0



We calculate terms in parentheses: -(2+4(-2r+2)), so:

2+4(-2r+2)

determiningTheFunctionDomain
4(-2r+2)+2

We multiply parentheses

-8r+8+2

We add all the numbers together, and all the variables

-8r+10

Back to the equation:

-(-8r+10)



We add all the numbers together, and all the variables

-11r-(-8r+10)-15=0

We get rid of parentheses

-11r+8r-10-15=0

We add all the numbers together, and all the variables

-3r-25=0

We move all terms containing r to the left, all other terms to the right

-3r=25

r=25/-3

r=-8+1/3

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