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1/2(a+2)=1/4(2-a)
We move all terms to the left:
1/2(a+2)-(1/4(2-a))=0
Domain of the equation: 2(a+2)!=0
a∈R
Domain of the equation: 4(2-a))!=0We add all the numbers together, and all the variables
a∈R
1/2(a+2)-(1/4(-1a+2))=0
We calculate fractions
(4a(-)/(2(a+2)*4(-1a+2)))+(-2aa/(2(a+2)*4(-1a+2)))=0
We calculate terms in parentheses: +(4a(-)/(2(a+2)*4(-1a+2))), so:
4a(-)/(2(a+2)*4(-1a+2))
We add all the numbers together, and all the variables
4a0/(2(a+2)*4(-1a+2))
We multiply all the terms by the denominator
4a0
We add all the numbers together, and all the variables
4a
Back to the equation:
+(4a)
We calculate terms in parentheses: +(-2aa/(2(a+2)*4(-1a+2))), so:We get rid of parentheses
-2aa/(2(a+2)*4(-1a+2))
We multiply all the terms by the denominator
-2aa
Back to the equation:
+(-2aa)
4a-2aa=0
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