2(u+2)+u=3(u+1)+6

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Solution for 2(u+2)+u=3(u+1)+6 equation: 



2(u+2)+u=3(u+1)+6

We move all terms to the left:

2(u+2)+u-(3(u+1)+6)=0

We add all the numbers together, and all the variables

u+2(u+2)-(3(u+1)+6)=0

We multiply parentheses

u+2u-(3(u+1)+6)+4=0



We calculate terms in parentheses: -(3(u+1)+6), so:

3(u+1)+6

We multiply parentheses

3u+3+6

We add all the numbers together, and all the variables

3u+9

Back to the equation:

-(3u+9)



We add all the numbers together, and all the variables

3u-(3u+9)+4=0

We get rid of parentheses

3u-3u-9+4=0

We add all the numbers together, and all the variables

-5!=0

There is no solution for this equation

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