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3x-10=2(x-5)+x
We move all terms to the left:
3x-10-(2(x-5)+x)=0
We calculate terms in parentheses: -(2(x-5)+x), so:We get rid of parentheses
2(x-5)+x
We add all the numbers together, and all the variables
x+2(x-5)
We multiply parentheses
x+2x-10
We add all the numbers together, and all the variables
3x-10
Back to the equation:
-(3x-10)
3x-3x+10-10=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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