1/2(6x-10)=1/5(25x-15)

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Solution for 1/2(6x-10)=1/5(25x-15) equation:



1/2(6x-10)=1/5(25x-15)
We move all terms to the left:
1/2(6x-10)-(1/5(25x-15))=0
Domain of the equation: 2(6x-10)!=0
x∈R
Domain of the equation: 5(25x-15))!=0
x∈R
We calculate fractions
(5x2/(2(6x-10)*5(25x-15)))+(-2x6/(2(6x-10)*5(25x-15)))=0
We calculate terms in parentheses: +(5x2/(2(6x-10)*5(25x-15))), so:
5x2/(2(6x-10)*5(25x-15))
We multiply all the terms by the denominator
5x2
We add all the numbers together, and all the variables
5x^2
Back to the equation:
+(5x^2)
We calculate terms in parentheses: +(-2x6/(2(6x-10)*5(25x-15))), so:
-2x6/(2(6x-10)*5(25x-15))
We multiply all the terms by the denominator
-2x6
We add all the numbers together, and all the variables
-2x^6
We do not support expression: x^6

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