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x-2(2-3x)=9+5(3x-1)
We move all terms to the left:
x-2(2-3x)-(9+5(3x-1))=0
We add all the numbers together, and all the variables
x-2(-3x+2)-(9+5(3x-1))=0
We multiply parentheses
x+6x-(9+5(3x-1))-4=0
We calculate terms in parentheses: -(9+5(3x-1)), so:We add all the numbers together, and all the variables
9+5(3x-1)
determiningTheFunctionDomain 5(3x-1)+9
We multiply parentheses
15x-5+9
We add all the numbers together, and all the variables
15x+4
Back to the equation:
-(15x+4)
7x-(15x+4)-4=0
We get rid of parentheses
7x-15x-4-4=0
We add all the numbers together, and all the variables
-8x-8=0
We move all terms containing x to the left, all other terms to the right
-8x=8
x=8/-8
x=-1
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