-4k2-8k-3=-3-5k2

Solution for -4k2-8k-3=-3-5k2 equation:

-4k^2-8k-3=-3-5k^2

We move all terms to the left:

-4k^2-8k-3-(-3-5k^2)=0

We get rid of parentheses

-4k^2+5k^2-8k+3-3=0

We add all the numbers together, and all the variables

k^2-8k=0

a = 1; b = -8; c = 0;
Δ = b2-4ac
Δ = -82-4·1·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8}{2*1}=\frac{0}{2}
=0
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8}{2*1}=\frac{16}{2}
=8
$