1(22+x)=4(4+x)

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Solution for 1(22+x)=4(4+x) equation: 



1(22+x)=4(4+x)

We move all terms to the left:

1(22+x)-(4(4+x))=0

We add all the numbers together, and all the variables

1(x+22)-(4(x+4))=0



We calculate terms in parentheses: -(4(x+4)), so:

4(x+4)

We multiply parentheses

4x+16

Back to the equation:

-(4x+16)



We get rid of parentheses

1(x+22)-4x-16=0

We add all the numbers together, and all the variables

-4x+1(x+22)-16=0

We move all terms containing x to the left, all other terms to the right

-4x+1(x+22)=16

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