7(5+x)=25(19+3x)

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Solution for 7(5+x)=25(19+3x) equation:



7(5+x)=25(19+3x)
We move all terms to the left:
7(5+x)-(25(19+3x))=0
We add all the numbers together, and all the variables
7(x+5)-(25(3x+19))=0
We multiply parentheses
7x-(25(3x+19))+35=0
We calculate terms in parentheses: -(25(3x+19)), so:
25(3x+19)
We multiply parentheses
75x+475
Back to the equation:
-(75x+475)
We get rid of parentheses
7x-75x-475+35=0
We add all the numbers together, and all the variables
-68x-440=0
We move all terms containing x to the left, all other terms to the right
-68x=440
x=440/-68
x=-6+8/17

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