p+(2/3*p)+(1/2*p)=234

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Solution for p+(2/3*p)+(1/2*p)=234 equation: 



p+(2/3p)+(1/2p)=234

We move all terms to the left:

p+(2/3p)+(1/2p)-(234)=0



Domain of the equation: 3p)!=0

p!=0/1

p!=0

p∈R





Domain of the equation: 2p)!=0

p!=0/1

p!=0

p∈R



We add all the numbers together, and all the variables

p+(+2/3p)+(+1/2p)-234=0

We get rid of parentheses

p+2/3p+1/2p-234=0

We calculate fractions


p+4p/6p^2+3p/6p^2-234=0

We multiply all the terms by the denominator


p*6p^2+4p+3p-234*6p^2=0

We add all the numbers together, and all the variables

7p+p*6p^2-234*6p^2=0

Wy multiply elements

6p^3-1404p^2+7p=0

We do not support eppression: p^3

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