3(22+x)=4(10+x)

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Solution for 3(22+x)=4(10+x) equation: 



3(22+x)=4(10+x)

We move all terms to the left:

3(22+x)-(4(10+x))=0

We add all the numbers together, and all the variables

3(x+22)-(4(x+10))=0

We multiply parentheses

3x-(4(x+10))+66=0



We calculate terms in parentheses: -(4(x+10)), so:

4(x+10)

We multiply parentheses

4x+40

Back to the equation:

-(4x+40)



We get rid of parentheses

3x-4x-40+66=0

We add all the numbers together, and all the variables

-1x+26=0

We move all terms containing x to the left, all other terms to the right

-x=-26

x=-26/-1

x=+26

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