0.4+x/(0.3-x)(0.2-x)=20

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Solution for 0.4+x/(0.3-x)(0.2-x)=20 equation: 



0.4+x/(0.3-x)(0.2-x)=20

We move all terms to the left:

0.4+x/(0.3-x)(0.2-x)-(20)=0



Domain of the equation: (0.3-x)(0.2-x)!=0

We move all terms containing x to the left, all other terms to the right

-x)(0.2-x!=-0.3

x∈R



We add all the numbers together, and all the variables

x/(-1x+0.3)(-1x+0.2)+0.4-20=0

We add all the numbers together, and all the variables

x/(-1x+0.3)(-1x+0.2)-19.6=0

We multiply parentheses ..

x/(+x^2-0.2x-0.3x+0.06)-19.6=0

We multiply all the terms by the denominator


-(19.6)*(+x^2-0.2x-0.3x+0.06)+x=0

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