.1/3x-4=3/4x+1

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Solution for .1/3x-4=3/4x+1 equation:



.1/3x-4=3/4x+1
We move all terms to the left:
.1/3x-4-(3/4x+1)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 4x+1)!=0
x∈R
We get rid of parentheses
.1/3x-3/4x-1-4=0
We calculate fractions
(.1*4x)/12x^2+(-9x)/12x^2-1-4=0
We add all the numbers together, and all the variables
(+.1*4x)/12x^2+(-9x)/12x^2-1-4=0
We add all the numbers together, and all the variables
(+.1*4x)/12x^2+(-9x)/12x^2-5=0
We multiply all the terms by the denominator
(+.1*4x)+(-9x)-5*12x^2=0
Wy multiply elements
-60x^2+(+.1*4x)+(-9x)=0
We get rid of parentheses
-60x^2+.1*4x-9x=0
We add all the numbers together, and all the variables
-60x^2-9x+.1*4x=0

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