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(1/3)(2x-4)=-6
We move all terms to the left:
(1/3)(2x-4)-(-6)=0
Domain of the equation: 3)(2x-4)!=0We add all the numbers together, and all the variables
x∈R
(+1/3)(2x-4)-(-6)=0
We add all the numbers together, and all the variables
(+1/3)(2x-4)+6=0
We multiply parentheses ..
(+2x^2+1/3*-4)+6=0
We multiply all the terms by the denominator
(+2x^2+1+6*3*-4)=0
We get rid of parentheses
2x^2+1-4+6*3*=0
We add all the numbers together, and all the variables
2x^2=0
a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{4}=0$
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