2x-7(x+2)=6(x-2)

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Solution for 2x-7(x+2)=6(x-2) equation:



2x-7(x+2)=6(x-2)
We move all terms to the left:
2x-7(x+2)-(6(x-2))=0
We multiply parentheses
2x-7x-(6(x-2))-14=0
We calculate terms in parentheses: -(6(x-2)), so:
6(x-2)
We multiply parentheses
6x-12
Back to the equation:
-(6x-12)
We add all the numbers together, and all the variables
-5x-(6x-12)-14=0
We get rid of parentheses
-5x-6x+12-14=0
We add all the numbers together, and all the variables
-11x-2=0
We move all terms containing x to the left, all other terms to the right
-11x=2
x=2/-11
x=-2/11

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