-8y+6(y-3)=-28

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Solution for -8y+6(y-3)=-28 equation: 



-8y+6(y-3)=-28

We move all terms to the left:

-8y+6(y-3)-(-28)=0

We add all the numbers together, and all the variables

-8y+6(y-3)+28=0

We multiply parentheses

-8y+6y-18+28=0

We add all the numbers together, and all the variables

-2y+10=0

We move all terms containing y to the left, all other terms to the right

-2y=-10

y=-10/-2

y=+5

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