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10(v+3)-4v=2(3v+3)-9
We move all terms to the left:
10(v+3)-4v-(2(3v+3)-9)=0
We add all the numbers together, and all the variables
-4v+10(v+3)-(2(3v+3)-9)=0
We multiply parentheses
-4v+10v-(2(3v+3)-9)+30=0
We calculate terms in parentheses: -(2(3v+3)-9), so:We add all the numbers together, and all the variables
2(3v+3)-9
We multiply parentheses
6v+6-9
We add all the numbers together, and all the variables
6v-3
Back to the equation:
-(6v-3)
6v-(6v-3)+30=0
We get rid of parentheses
6v-6v+3+30=0
We add all the numbers together, and all the variables
33!=0
There is no solution for this equation
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